The radii of a cylinder and a cone are equal. | vedclass

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(B) Let the radius of both the cylinder and the cone be $r$.Let the height of the cylinder be $h$ and the slant height of the cone be $l$.Given that t

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$2$

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(B) Let the radius of both the cylinder and the cone be $r$.Let the height of the cylinder be $h$ and the slant height of the cone be $l$.Given that the height of the cylinder is equal to the slant height of the cone,so $h = l$.The curved surface area of the cylinder is $CSA_{cylinder} = 2 \pi r h$.The curved surface area of the cone is $CSA_{cone} = \pi r l$.Since $h = l$,we can substitute $l$ with $h$ in the formula for the cone's curved surface area: $CSA_{cone} = \pi r h$.The ratio of the curved surface area of the cylinder to the cone is $\frac{2 \pi r h}{\pi r h} = \frac{2}{1}$.Therefore,the required ratio is $2:1$.

The radii of a cylinder and a cone are equal. If the height of the cylinder is equal to the slant height of the cone,then the ratio of the curved surface areas of the cylinder and the cone is: (in $:1$)

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